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如何限流led燈珠 led燈為什么要限流

發布時間:2022-10-24 09:30:52

大家好我是小編燈(deng)(deng)(deng)漂亮今天我們(men)來介(jie)紹如何限流led燈(deng)(deng)(deng)珠 led燈(deng)(deng)(deng)為什(shen)么(me)要限流的(de)問(wen)題(ti),以(yi)下就是燈(deng)(deng)(deng)漂亮對此(ci)問(wen)題(ti)和相關問(wen)題(ti)的(de)歸納整理,一起來看(kan)看(kan)吧。

文章目錄導航:

led燈珠電流過大解決辦法

LED燈(deng)珠電流過大的解(jie)決辦法,可以加限(xian)流電阻(zu)或降(jiang)低電壓來解(jie)決。

如何限流led燈珠

led燈電壓有點高怎么限流

led燈內一(yi)般都會有個整流(liu)回路(lu),跟分壓(ya)限(xian)流(liu)回路(lu),將電(dian)壓(ya)整成直流(liu),然后分壓(ya)限(xian)流(liu),使led兩端(duan)的(de)壓(ya)降(jiang)接近去(qu)工作電(dian)壓(ya),并使的(de)電(dian)流(liu)不超過其(qi)工作電(dian)流(liu),這樣就能正常工作。

電(dian)阻(zu)rl是負載電(dian)阻(zu),r為(wei)穩壓(ya)(ya)調整電(dian)阻(zu)也稱為(wei)限(xian)流(liu)電(dian)阻(zu),d為(wei)穩壓(ya)(ya)管.按穩壓(ya)(ya)電(dian)路設計(ji)準則,在(zai)輸入(ru)電(dian)壓(ya)(ya)基本不變(bian)時(shi),rl變(bian)小時(shi),流(liu)過rl的(de)電(dian)流(liu)增(zeng)加,但流(liu)過d的(de)電(dian)流(liu)卻減少.

led怎么串限流電阻

1.LED燈珠(zhu)串聯細流電阻需要做到以下步驟(zou)。

2.第一步,先要(yao)明(ming)(ming)確(que)加載LED限流(liu)電阻(zu)兩(liang)端(duan)之間的(de)(de)電壓大小是(shi)(shi)多(duo)少(shao)。第二步,要(yao)明(ming)(ming)確(que)LED通過的(de)(de)電流(liu)是(shi)(shi)多(duo)少(shao),還(huan)有它(ta)的(de)(de)額(e)定(ding)電壓是(shi)(shi)多(duo)少(shao)。第三步,根(gen)據LED限流(liu)電阻(zu)公式(shi)進行計算限流(liu)電阻(zu)的(de)(de)大小即

R=u-led(on)/i

3.這(zhe)里面的(de)r表(biao)示電(dian)阻的(de)阻值,U則代(dai)表(biao)家在限流(liu)(liu)電(dian)阻和LED之間的(de)電(dian)壓,I表(biao)示流(liu)(liu)過LED的(de)電(dian)流(liu)(liu)大小。這(zhe)樣就可以計算出(chu)LED的(de)限流(liu)(liu)電(dian)阻是多少。

led燈珠限流電阻值的計算方法

LED燈(deng)串聯電(dian)(dian)阻,要看其應用(yong)場合和燈(deng)的(de)種類,比如(ru)220V電(dian)(dian)源 如(ru)果使用(yong)LED做為(wei)指示燈(deng),不同廠家、不同顏色(se)的(de)LED在不同的(de)應用(yong)場合中,限流電(dian)(dian)阻的(de)阻值都不一樣。

限流電(dian)阻計算公式為(wei):(電(dian)源電(dian)壓(ya)V-LED壓(ya)降V)÷限流電(dian)流A=電(dian)阻值Ω。

以220V,普通紅色(se)的(de)LED為例,壓(ya)降(jiang)取2V,電流(liu)取2mA,限(xian)流(liu)電阻為120KΩ。

由于LED僅需(xu)微弱電流即可(ke)點亮,出(chu)于安全和保(bao)障長時間正(zheng)常使用(yong)考(kao)慮,可(ke)以(yi)取值150KΩ - 500KΩ,功率1/4W以(yi)上的標準電阻。

(單顆3W750mA)LED燈珠3個串聯如何限流電阻呢

一般來說(shuo)LED的(de)(de)(de)工(gong)作電(dian)(dian)(dian)(dian)(dian)(dian)(dian)壓(ya)(ya)(ya)是(shi)2-3.6V,你(ni)說(shuo)的(de)(de)(de)3W和0.75A至少(shao)(shao)有一個(ge)(ge)是(shi)錯的(de)(de)(de)。如果你(ni)串(chuan)(chuan)聯(lian)了電(dian)(dian)(dian)(dian)(dian)(dian)(dian)阻(zu)后(hou)光(guang)會(hui)(hui)變暗(an)就是(shi)電(dian)(dian)(dian)(dian)(dian)(dian)(dian)阻(zu)太大(da)了,正(zheng)常發(fa)光(guang)時電(dian)(dian)(dian)(dian)(dian)(dian)(dian)阻(zu)發(fa)熱是(shi)電(dian)(dian)(dian)(dian)(dian)(dian)(dian)阻(zu)的(de)(de)(de)功(gong)率太小。按平均2.8V算,3個(ge)(ge)LED共(gong)8.4V,電(dian)(dian)(dian)(dian)(dian)(dian)(dian)源多出(chu)3.6V,0.75A需要4.8Ω/2.7W的(de)(de)(de)電(dian)(dian)(dian)(dian)(dian)(dian)(dian)阻(zu)。 查(cha)清你(ni)用(yong)的(de)(de)(de)LED的(de)(de)(de)工(gong)作電(dian)(dian)(dian)(dian)(dian)(dian)(dian)壓(ya)(ya)(ya)和電(dian)(dian)(dian)(dian)(dian)(dian)(dian)流應該是(shi)多少(shao)(shao),然(ran)后(hou)計算出(chu)串(chuan)(chuan)聯(lian)電(dian)(dian)(dian)(dian)(dian)(dian)(dian)阻(zu)的(de)(de)(de)正(zheng)確阻(zu)值和功(gong)率。 此(ci)外注意(yi),LED是(shi)半導體(ti)器(qi)件,半導體(ti)器(qi)件的(de)(de)(de)離散性很大(da),所以即便是(shi)同型(xing)號,同批次的(de)(de)(de)LED,每個(ge)(ge)燈的(de)(de)(de)電(dian)(dian)(dian)(dian)(dian)(dian)(dian)壓(ya)(ya)(ya)的(de)(de)(de)電(dian)(dian)(dian)(dian)(dian)(dian)(dian)流也不完(wan)全相同(但相同型(xing)號和批次的(de)(de)(de)LED差別不會(hui)(hui)太大(da)),所以串(chuan)(chuan)聯(lian)時分壓(ya)(ya)(ya)會(hui)(hui)不均勻,導致有的(de)(de)(de)燈較亮,有的(de)(de)(de)燈較暗(an)。解決的(de)(de)(de)辦法是(shi)每個(ge)(ge)LED上并一個(ge)(ge)阻(zu)值較大(da)的(de)(de)(de)電(dian)(dian)(dian)(dian)(dian)(dian)(dian)阻(zu)(2.8V/7mA左右,電(dian)(dian)(dian)(dian)(dian)(dian)(dian)壓(ya)(ya)(ya)指燈的(de)(de)(de)工(gong)作電(dian)(dian)(dian)(dian)(dian)(dian)(dian)壓(ya)(ya)(ya)),平衡一部份電(dian)(dian)(dian)(dian)(dian)(dian)(dian)流差異。

以上就是天成(cheng)小編對(dui)于如何(he)限流led燈珠 led燈為什么要限流問(wen)題(ti)和相(xiang)關問(wen)題(ti)的解答了,希(xi)望對(dui)你有(you)用 【責任編輯(ji):燈漂亮】

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